Sikander Aqeel

ATMOSPHERE OF BERYLLIUM ON EARTH

Apr 4th 2017, 11:23 am
Posted by aqeelsika
481 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Beryllium formate 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

 

        a2 (25)          + b2 (16) = c2

 

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

 

Beryllium energy atmosphere = 99.5% * H0.55 of fusion = 54.725 hour 

 

                       Because 

                       Hour = 54.725 / 6 proton of C = 9.12-Fluorine  

                            = 9.12 – 4 proton of Be = 5.12-Boron

 

Fluorine  = 9 proton  

Boron = 5 proton

 

  Beryllium = 9.12 * 5.12 = 46.6944

            = 46.6944 + 52.8056% (CO2 + H7 = 52.75) = 99.5

            = 99.5

 

 Chemical = 99.5 - 24 (C2) formate atmosphere of earth = 75.5

          = 75.5 – 2.5 (H2) = 73 

          = 73 – 64 (O4) = 9 

          = 9 = Be = Beryllium 

 

 

Chemical formula from 54.725 hours = Be(CHO2)2  

                                   = Be(CHO2)2, beryllium formate 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 83.75% (H2O + O4 + H2 = 83.75) = 99.5

                          = 99.5 = Be(CHO2)2 = E = m2c,      

 

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