PROTEINS LAW OF SIKANDER AQEEL

ACETABULUM 

SYNTHESIS OF DISEASE  

LOOSE FEMUR INTO THE ACETABULUM 

Acetabulum! The cup-shaped hollow in the hipbone into which the head of the femur fits to form a ball and socket joint, 

Sometimes this hollow becomes loose and femur head moves free in the acetabulum hollow with sound, and it is defected joint function, some people operation of plastic on femur for fill the hollow, basically when a base becomes weak into the DNA then this loose bone process start, now here what are reasons of loose hollow, 

To find weak base, 

Lysine Helps form collagen, the connective tissue present in bones, ligaments, tendons, and joints,  

Lysine = TTT TTC DNA base = AAA, AAG mRNA base = Adenine 

Weak base = Adenine = C5H5N5 = 135.13 m/g (A) 

Total DNA base = 523.47 – 135.13 (A) weak base = 388.34            

2 = Total DNA base = 523.47 = (A-T=C-G) 

1 = CaCO3 + CaSO4 = 236 

2 = weak DNA base = 388.34 = (0-T=C-G)      

ANSWER OF DISORDER 

Healthy disorders  

CaCO3 + CaSO4 = 236 

Weak DNA base = 388.34 = (0-T=C-G)      

A = CaCO3 + CaSO4 = 236 direct value      

B = Weak DNA base = 388.34 direct value

ANSWER OF DISORDER 

Too Sick disorders 

FORMULA TO FIND OUT MEDICINE OF DISEASES

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ACETABULUM 

SYNTHESIS OF DISEASE  

LOOSE FEMUR INTO THE ACETABULUM 

       CaCO3 + CaSO4 = 236

       Weak DNA base 388.34

       Acetabulum = Lycine + Adenine,   

        a2 + b2 = c2  

        a2 (Weak DNA base)   + b2 (CaCO3 + CaSO4) = c2  

        a2 (388.34)          + b2 (236)   

        a2 (150807.9556)     + b2 (55696) = c2 

        a2 + b2 = 206503.9556 = c2 

       TRANSCRIPTION

       = a2 + b2 = 206503.9556 = transcription 

       = a2 + b2 = 206503.9556 * 61 Carbohydrate = 12596741.2916

       = a2 + b2 = 12596741.2916 / 112.0868 Uracil = 112383.80

       = a2 + b2 = 112383.80 = Two helix of DNA 

Uracil + Cytosine = Pyrimidine  

Two helix of DNA = 112383.80 / 37 C human temperature = 3037.4

                 = 3037.4 / 183 glucose = 16.59

                 = 16.59 + 0.66 () = 17.25

                 = 17.25 = (-OH) of DNA helix 

       BEGINNER TRANSCRIPTION OF RNA

       = a2 + b2 = 112383.80 = beginner transcription of RNA 

       = a2 + b2 = 112383.80 * 347.5 Sucrose = 39053370.5

       = a2 + b2 = 39053370.5 / 135.13 Adenine = 289005.92

       = a2 + b2 = 289005.92

Adenine + Guanine = Purine 

                     BEGINNER TRANSCRIPTION OF RNA

Transcription of RNA = 289005.92 / 511 ATP = 565.56

                     = 565.56 - 13.06 (CH) = 552.5   

                     = = 552.5 g/mol = (CaH2)- 13 of DNA   

Carboxyl group occurs too much prepared of mRNA, tRNA, rRNA,    

 AMINO ACIDS OF mRNA 

 = a2 + b2 = 289005.92 / 134.53 (weak Adenine = 134.53) = 2148.26 

 = a2 + b2 = 2148.14 = (Polymerase enzyme of RNA)

 = a2 + b2 = 2148.14 * 1.2961 (H) = 2784.21  

 = a2 + b2 = 2784.25 = 20 amino acids of mRNA from Polymerase enzyme 

tRNA FROM CYTOPLASM 

= a2 + b2 = 289005.92 * 7.4 pH blood plasma = 2138643.808

= a2 + b2 = 2138643.808 / 40 different cytoplasm in cell = 53466.0952

= a2 + b2 = 53466.0952 / 157.25 (Histidine) = 340.00(amino molecules)  

= a2 + b2 = 340.00 - 10.5 (H8 = 10) = 350.5

= a2 + b2 = 350.5 = (ADP) energy from Weak DNA base + CaCO3 + CaSO4,    

= a2 + b2 = 53466.0952 = tRNA, mRNA, rRNA from process of cytoplasm  

       MESSENGER mRNA

       = a2 + b2 = 53466.0952 / 46.25 chromosomes = 1156.02

       = a2 + b2 = 1156.02 information for the ribosomal (messenger mRNA)  

 INFORMATION OF MESSENGER = 1156.02

 = a2 + b2 = 1156.02 * 149.25 g/mol (Gln) = 172535.985

 = a2 + b2 = 172535.985 / 61.968% nucleated amino-acids move RNA = 2784.27

 = a2 + b2 = 2784.25 = 20 amino acids of polypeptide 

    = a2 + b2 = 2784.25 * 61.968 Mononucleotide = 172534.404

    = a2 + b2 = 172534.404 = molecular weight from 61.968 Mononucleotide 

    DAILY DIET   

    = a2 + b2 = 172534.404 / 5 (H3 + H2 of DNA) = 34506.8808

    = a2 + b2 = 34506.8808 + 493.1192 (Polypeptide) = 35,000

    = a2 + b2 = 35,000 = molecular weight of Pepsinogen protein, 

5 (H3 + H2 of DNA) = (A-T=C-G)   

PROTEIN

= a2 + b2 = 172534.404 * 23 pair chromosomes cell environment = 3968291.292

= a2 + b2 = 3968291.292 + 462.25 (Leucine + Gln + Purine) = 3968753.542

= a2 + b2 = 3968753.542 m/g protein from DNA helix + Chromosomes, 

Total protein = 3968753.542 / 64500 main hemoglobin = 61.53

              = 61.53 / 7.8 times protein = 7.8 times Vitamin-D, and we have already 61.968 phosphoric Mononucleotide for RNA DNA;   

SYNTHESIS OF DISEASES  

Formula of medicines 

Weak DNA base + CaCO3 + CaSO4 = perfect loose femur bone by many vitamins, and from deficiency of adenine. Or 134.53 weak Adenine, 

The Phenylalanine use will be better than operation of femur bone, and it will be called the doctorate of amino acids