Sikander Aqeel

GENETIC TEST OF GLOBULIN PROTEIN

Apr 4th 2017, 11:28 am
Posted by aqeelsika
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(Genetic blood test by Sikander Aqeel) 

DOCTORATE OF AMINO ACID

1 = Genetic test of Globulin protein  

 

A= Normal cells membranes = protein 55% + 6% carbohydrate + lipids 39% = 100 

A= Genetic cells membranes = protein 53% + 6% carbohydrate + lipids 41% = 100   

 

A = Genetic cells membranes = 157.25% His - 52.52% protein = 209.77

A = Genetic cells membranes = 209.77

 

Genetic function = 209.77% salt value  

 

 

B = Normal cell membranes = 100 % / 100 = 1 

                          = 1 * 209.77% = 209.77

                          = 209.77 * 6% normal = 1258.62

                          = 1258.62 * 55% normal = 69224.1

                          = 69224.1 / 100% = 692.24

                          = 692.25 mole = Five salt of blood plasma

 

Normal cell membrane = 100 

 

 

A = Blood plasma = Five salt = NaCl-58 m/g 

                             = NaHCO3-84.25 m/g 

                             = NaPO4-118 m/g 

                             = KClO3-122 m/g 

                             = Ca3(PO4)2-310 m/g 

                             = 692.25 m/g total salt in blood plasma 

 

B = Histidine = 157.25 

 

Amino acid 

Histidine = 157.25 

 

Genetic material    

Salt in blood plasma = 692.25

 

TO START CODON PROCESS

mRNA CODE 

Histidine-157.25 

Blood plasma-692.25 

 

TO START CODON SYSTEM

Histidine-157.25 + 692.25 Salt = 849.5 / 692.25 Salt = 1.22

1.22 * 692.25 Salt = 844.545

1.22 times Salt = 844.545

Uracil = C4H4N2O2 = 112.0868 g/mol = (U) 

 

 

        a2 + b2 [3Th part] = c2  

        a2 + b2 (amino acid) = c2  

 

        a2 (Uracil)           + b2 (60 minute) [amino acid] = c2  

        a2 (112.0868)         + b2 (60 minute) [amino acid] = c2   

        a2 (12563.45073424)   + b2 (3600) [amino acid] = c2 

 

        a2 + b2 = 16163.45 [amino acid] = c2 

        a2 + b2 = 16163.45 / 127.13 = 127.14 

 

        a2 + b2 = 127.14 * 844.545 (1.22 times Salt) = 107375.4513

        a2 + b2 = 107375.4513 / 3 triple RNA = 35791.8171

        a2 + b2 = 35791.8171 - 35076.1703% (Histidine-157.25) = 715.6468

        a2 + b2 = 715.6468 m/g = CAU CAC = His from Five Salt   

 

 

Histidine = 35076.1703% / 157.25 His = 223.05 sets in mRNA 

Histidine = CAU CAC

 

 

        JOINING OF ADENINE WITH THYMINE 

        JOINING OF GUANINE WITH CYTOSINE 

 

      Start 

      a2 + b2 = 16163.45 / 715.6468 His = 22.58 or 23 amino acids to take start from CCA-Proline mRNA  

 

      End 

      a2 + b2 = 715.6468 His = No. 38 = CAC-Histidine mRNA end 

 

        JOINING OF ADENINE GUANINE = PURINE 

        JOINING OF URACIL CYTOSINE = PYRIMIDINE 

 

 

        FOR STOP TO RNA 

        If started from left side to codon chart 

        Then Start = CCA-Proline mRNA = 23 amino acid,  

        Then End = CAC-Histidine mRNA = 38 amino acids,  

 

DIFFERENT START AND END = DIFFERENT PROTEIN AND DISEASES

Or to make protein under the Histidine + Proline use only 15-GUA-Valine operating codes of RNA, 

Start = 38 – 23 end = 15-GUA-Valine acid operating codon RNA 

 

SOLUTION OF GENETIC DISEASES      

Start CCA-Proline = A third base 

End CAC-Histidine mRNA = C third base 

Center GUA-Valine = A third base  

 

Total third base  

 

Up to down = ACA  

Down to up = ACA

Center = CAA AAC 

 

TOTAL THIRD BASE     

HEALTHY MUTATION

mRNA ACA Threonine = Threonine DNA base TGC = ?-T=C-G = 1 A 

mRNA ACA Threonine = Threonine DNA base TGA = A-T=C-G = Complete   

 

mRNA CAA Proline = Proline DNA base g GGA = A-?=?-G = 2 TC 

mRNA AAC Asparagine = Asparagine DNA base CTA = A-T=C-G = Complete  

 

GENETIC REPORT OF BLOOD TEST

Complete First helix = ATTGCAT  

Complete Second helix = TAACGTA 

 

Missed base = ?TTGCAT = 1 A  

Missed base = ?AA?GTA = 2 TC  

 

Total Missed base = ??TG?AT = ATC Tyrosine DNA base from UGA mRNA 

                            = UAG = Tyrosine 

 

Genetic report of globulin protein in blood = ATC 

 

The mRNA has main Tyrosine, Which found too much in globulin protein, 

 

 

GENETIC TEST OF GLOBULIN PROTEIN OF ACETABULUM 

One alphabet always use three time, such as we have four TTTT, that three T of test and one T of helix, total four T, so One alphabet always use three time like TTT  

 

Acetabulum = AA + ATC Globulin test + A-T=C-G = AAAA-TT=CC-G 

Acetabulum Globulin test report = AAA-TT=CC-G

Acetabulum Globulin test report = AAA-TTC=C-G 

Acetabulum Globulin test report = AAA-TTC

 

Acetabulum = AAA Phenylalanine A blank gap or missing part or missing bone cell from neurotransmitters action 

 

Acetabulum = TTC Lysine Helps form collagen, the connective tissue present in bones, ligaments, tendons, and joints, 

 

The Phenylalanine use will be better than operation of femur bone, and it will be called the doctorate of amino acids     

 

So in the doctorate of amino acid we shall use genetic blood test system, urine test, liver test, actually all body test would be contain on genetic test system,  

 

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