Sikander Aqeel

ATMOSPHERE OF BERYLLIUM ON EARTH

Apr 6th 2017, 12:17 pm
Posted by aqeelsika
494 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Beryllium acetylacetonate 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

 

        a2 (25)          + b2 (16) = c2

 

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

 

Beryllium energy atmosphere = 210.5% * H0.55 of fusion = 115.775 hour 

 

                       Because 

                       Hour = 115.775 / 6 proton of C = 19.29- Potassium  

                            = 19.29 – 4 proton of Be = 15.29-Phosphorus 

 

Potassium = 19 proton  

Phosphorus = 15 proton

 

  Beryllium = 19.29 * 15.29 = 294.9441

            = 294.9441 + 84.4441% (2H2O = 37) = 210.5

            = 210.5

 

 Chemical = 210.5 - 120 (C10) acetyl atmosphere of earth (Organic) = 90.5

          = 90.5 – 17.5 (H14) = 73 

          = 73 – 64 (O4) = 9 

          = 9 = Be = Beryllium 

 

 

Chemical formula from 115.775 hours = Be(C5H7O2)2  

                                    = Be(C5H7O2)2, beryllium acetylacetonate 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 39.58% (2H2O + H2 = 39.5) = 210.5

                          = 210.5 = Be(C5H7O2)2 = E = m2c,      

 

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