ATMOSPHERE OF BERYLLIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Beryllium fluoride 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

        a2 (25)          + b2 (16) = c2

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

Beryllium energy atmosphere = 47% * H0.55 of fusion = 25.85 hour 

                       Because 

                       Hour = 25.85 / 3 proton of Li = 8.61-Fluorine  

                            = 8.61 – 4 proton of Be = 4.61-Boron 

Fluorine = 9 proton  

Boron = 5 proton 

  Beryllium = 8.61 * 4.61 = 39.6921

            = 39.6921 + 7.3079% (Li = 7) = 47

            = 47

 Chemical = 47 - 38 (F2) oxidizing agent atmosphere of earth = 9

          = 9 = Be = Beryllium 

Chemical formula from 25.85 hours = BeF2  

                                    = BeF2, beryllium fluoride 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 177.30% (5H2O + H9 = 177.75) = 47

                          = 47 = BeF2 = E = m2c,