GENETIC TEST OF INSULIN

(Genetic test by Sikander Aqeel) 

DOCTORATE OF AMINO ACID

1 = Genetic test of Insulin 

A= Normal cells membranes = protein 55% + 6% carbohydrate + lipids 39% = 100 

A = Insulin cells membranes = 169.18 V-B6 + 177.5 Arg + 5.33C(H2O) = 162.565 = 509.245 

Vitamin-B6 = 169.18 

Arginine = 177.5    

5.33 carbohydrate = 162.565 

            Total = 509.245  

                            = 509.245 - 55% protein = 454.245

A = Insulin cells membranes = 454.245

CSF function = 454.245% value of Insulin   

B = Normal cell membranes = 100 % / 100 = 1 

                          = 1 * 454.245% = 454.245

                          = 454.245 * 6% normal = 2725.47

                          = 2725.47 * 55% normal = 149900.85

                          = 149900.85 / 100% = 1499.00

                          = 1499.00 Insulin or hormone release value 

                          = 1499.00 Vitamin-B6 + Arginine + carbohydrate 

Normal cell membrane = 100 

A = Insulin = 1499.00 = Insulin or hormone production 

Here we shall use amount of vitamin-B6 for Insulin,  

    Insulin = 1499.00 - 169.18 vitamin-B6 = 1329.82

            = 1329.82 – 183.75-Tyrosine = 1146.07

            = 1146.07 / 33.85 = 33.85

            = 33.85 + 33.85 = 67.7

            = 67.7 - 2.7 H2 = 65

            = 65 = Zn = Zinc-65  

Vitamin-B6 as used for diabetes

Tyrosine-183.75 is most important amino acid to produce hormones or insulin  

Zinc-65 does the dry to wounds or cells wall from over insulin in blood,   

Amino acid 

Tyrosine-183.75 

Genetic metal    

Zinc-65 

TO START CODON PROCESS

mRNA CODE 

Tyrosine-183.75 

Zinc-65

TO START CODON SYSTEM

Tyrosine-183.75 + 65 Zn = 248.75 / 65 Zn = 3.82

3.82 * 65 Zn = 248.3

3.82 times Zinc = 248.3

Uracil = C4H4N2O2 = 112.0868 g/mol = (U) 

        a2 + b2 [3Th part] = c2  

        a2 + b2 (amino acid) = c2  

        a2 (Uracil)           + b2 (60 minute) [amino acid] = c2  

        a2 (112.0868)         + b2 (60 minute) [amino acid] = c2   

        a2 (12563.45073424)   + b2 (3600) [amino acid] = c2 

        a2 + b2 = 16163.45 [amino acid] = c2 

        a2 + b2 = 16163.45 / 127.13 = 127.14 

        a2 + b2 = 127.14 * 248.3 (3.73 times Zinc) = 31568.862

        a2 + b2 = 31568.862 / 3 triple RNA = 10522.954

        a2 + b2 = 10522.954 - 9805.3336% (Tyrosine-183.75) = 717.6204

        a2 + b2 = 717.6204 m/g = UAU UAC = Tyr from Zn   

Tyrosine = 9805.3336% / 183.75 Tyr = 53.36 sets in mRNA 

Tyrosine = UAU UAC

        JOINING OF ADENINE WITH THYMINE 

        JOINING OF GUANINE WITH CYTOSINE  

Tyrosine = UAU UAC = 717.6204 + 65 Zn = 782.6204  

      Start 

      a2 + b2 = 16163.45 / 782.6204 Tyr + Zn = 20.65 or 21 amino acids to take start from CCU-Proline mRNA  

      End 

      a2 + b2 = 717.6204 Tyr = No. 33 = UAU-Tyrosine mRNA end 

        JOINING OF ADENINE GUANINE = PURINE 

        JOINING OF URACIL CYTOSINE = PYRIMIDINE 

        FOR STOP TO RNA 

        If started from left side to codon chart 

        Then Start = CCU-Proline mRNA = 21 amino acid,  

        Then End = UAU-Tyrosine mRNA = 33 amino acids,  

DIFFERENT START AND END = DIFFERENT PROTEIN AND DISEASES

Or to make hemoglobin under the Tyrosine + Proline use only 12-AUG-Methionine operating codes of RNA, 

End = 33 – 21 start = 12-AUG-Methionine operating codon RNA 

SOLUTION OF GENETIC DISEASES      

Start CCU-Proline = U third base 

End UAC-Tyrosine mRNA = C third base 

Center AUG-Methionine = G third base  

Total third base  

Up to down = UCG  

Down to up = GCU

Center = CUG CGU 

TOTAL THIRD BASE     

HEALTHY MUTATION

mRNA UCG 4th Serine = Serine 4th DNA base AGC = A-?=C-G = 1 T 

mRNA GCU 1th Alanine = Alanine first DNA base CGA = A-?=C-G --1 T   

mRNA CUG 4th Leucine = Leucine 4th DNA base GAG = A-?=?-G = 2 TC 

mRNA CGU 1th Arginine = Arginine first DNA base GCA = A-?=C-G = 1 T  

GENETIC REPORT OF INSULIN TEST

Complete First helix = ATTGCAT  

Complete Second helix = TAACGTA 

Missed base = A??GCA? = 4 T  

Missed base = A?TG?AT = 1 C 

             Insulin = TTTTC 

Total Missed base = TTT-TC = Lysine 

Insulin report TTT-TC = AAA, AAG, UAU, tRNA = Lysine 

Insulin report TTT-TC = UUU, UUC, AUA, mRNA = Lysine 

Insulin report TTT-TC = TTT, TTC, TAT, DNA = Lysine   

Insulin genetic report = TTT-TC = Lysine 

Lysine Involved in hormone production,  

GENETIC TEST OF INSULIN FOR ACETOACETIC ACID   

Insulin genetic report = TTT-TC

Acetoacetic acid = CGC 

Acetoacetic acid = CGC + TTT-TC (Insulin report) = -TTTT=CCC-G 

Acetoacetic acid = Insulin genetic report = TTT=TCC-CG

Acetoacetic acid = Insulin genetic report = TTT=TCC

Acetoacetic acid = TTT DNA base = Lysine Involved in hormone production, 

Acetoacetic acid = TCC DNA base = Arginine release insulin in shape of hormone, 

If Acetoacetic acid is present in diabetes then pancreas need is Lysine and Arginine,      

And we have right genetic Insulin test, never say me billion and billion years later, Sikander Aqeel why you did not teach us about modern genetic biology, 

GENETIC DOCTORATE OF AMINO ACIDS, 

Today our need is modern genetic doctorate to stop time of cells; the human cells change it every year, our need is a genetic doctorate where is a choice to life, supposed you want live in teen age whole life, or you want live in 30 year age whole life, then genetic doctorate will provide you this all bio-conditions, 

TYPES OF MUTATION 

1 = newborn = very light Translation of protein by light mutation 

1 = newborn = soft skin by first type of mutation 

The newborn is first light mutation where from mutation clock start, now newborn body will produce one percent heavy protein and hormone to go in second year age, where they start to walk, but they cannot run, therefore newborn body will produce two percent heavy protein and hormone to go in third year age, where they will start to run,  

Now supposed genetic code of newborn start from first Alanine amino acid till the 4.5 year, or every genetic code works till 4.5 year, 

because 4.5 year * 20 amino acid = 90 year last age, 

now after 4.5 year the child genetic code will transfer or jump in second amino acid for next 4.5 year, and this transfer or jump will called mutation in body, because body shape has too much difference of 1 year to 9 year, 

FIRST + SECOND + THIRD MUTATION

Now first amino acid = 4.5 year = 1, 2, or 3 percent heavy protein, 

And first + second amino acid = 9 year = like 4, 5, 6, percent heavy protein, 

Now first + second + third amino acid = 13.5 year age, now child start to understand everything, or they will asked to you, that what is all this, or they will try to get everything, 

Now supposed we shut 50% the all doors of 17 amino acid after third amino acid, then child growth or mutation would be too slow to go in ** age, and after some year their ** function totally finished from body, always remember each amino acid 100% work to go in last age on own time,