Sikander Aqeel

ATMOSPHERE OF BERYLLIUM ON EARTH

Apr 11th 2017, 11:23 am
Posted by aqeelsika
481 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Beryllium Oxide 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

 

        a2 (25)          + b2 (16) = c2

 

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

 

Beryllium energy atmosphere = 25% * H0.55 of fusion = 13.75 hour 

 

                       Because 

                       Hour = 13.75 / 2 proton of He = 6.875-Nitrogen  

                            = 6.875 – 4 proton of Be = 2.875-hydrogen 

 

Nitrogen = 7 proton  

Hydrogen = 2.5 (H2) proton 

 

  Beryllium = 6.875 * 2.875 = 19.765625

            = 19.765625 + 5.234375% (He + H = 5.25) = 25

            = 25

 

Chemical = 25 - 16 (O1) any oxygen compound atmosphere of earth = 9

         = 9 = Be = Beryllium 

 

 

Chemical formula from 13.75 hours = BeO  

                                  = BeO, beryllium Oxide 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 333.3332% (21O = 336) = 25

                          = 25 = BeO = E = m2c,       

 

 

Bookmark & Share:

Please Like Us
Please Like Us