ATMOSPHERE OF BERYLLIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Beryllium Hydroxide 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

        a2 (25)          + b2 (16) = c2

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

Beryllium energy atmosphere = 43.5% * H0.55 of fusion = 23.925 hour 

                       Because 

                       Hour = 23.925 / 2 proton of He = 11.9625-Magnesium  

                            = 11.9625 – 4 proton of Be = 7.9625-Oxygen 

Magnesium = 12 proton  

Oxygen = 8 proton 

  Beryllium = 11.9625 * 7.9625 = 95.25140625

            = 95.25140625 - 51.75140625% (2H2O + CH = H = 51.5) = 43.5

            = 43.5

Chemical = 43.5 - 34.5 (OH)2 hydroxyl atmosphere of earth = 9

         = 9 = Be = Beryllium 

Chemical formula from 23.925 hours = Be(OH)2  

                                   = Be(OH)2, beryllium Hydroxide 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 191.57% (OH)11 + H = 191) = 43.5

                          = 43.5 = Be(OH)2 = E = m2c,