ATMOSPHERE OF BERYLLIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Beryllium Sulfate 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

        a2 (25)          + b2 (16) = c2

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

Beryllium energy atmosphere = 105% * H0.55 of fusion = 57.75 hour 

                       Because 

                       Hour = 57.75 / 6 proton of C = 9.625-Neon  

                            = 9.625 – 4 proton of Be = 5.625-Carbon 

Neon = 10 proton  

Carbon = 6 proton 

  Beryllium = 9.625 * 5.625 = 54.140625

            = 54.140625 + 50.859375% (2H2O + N = 51) = 105

            = 105

Chemical = 105 - 32 (S) Sulphuric atmosphere of earth = 73 

         = 73 - 64 (O4) = 9 

         = 9 = Be = Beryllium 

Chemical formula from 57.75 hours = BeSO4  

                                  = BeSO4, beryllium Sulfate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 79.365% (H2O)4 + H5 = 79) = 105

                          = 105 = BeSO4 = E = m2c,