ENERGY LAW IS EQUAL TO E = m2c
ACETONURIA
SYNTHESIS OF DISEASE
TO BE EXCESSIVE AMOUNTS OF KETONE BODIES IN URINE OF DIABETES
Acetonuria! Excessive amounts of ketone bodies in the urine as in diabetes mellitus or starvation
WITHOUT DRUG TREATMENT
1 = Acetoacetic acid = C4H6O3 = 102.0886 g/mol
2 = Acetone = C3H6O = 58.08 g/mol
3 = β-Hydroxybutyric acid = C4H7O2 = 88.75
Total ketone bodies = 248.9186
1 = Acetonuria = 248.9186
2 = DNA helix = 523.47 = (A-T=C-G)
ANSWER OF DISORDER
Healthy disorders
A = Acetonuria = 248.9186 direct value
B = DNA helix = 523.47 = (A-T=C-G) direct value
ANSWER OF DISORDER
Too Sick disorders
FORMULA TO FIND OUT MEDICINE OF DISEASES
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ACETONURIA
SYNTHESIS OF DISEASE
TO BE EXCESSIVE AMOUNTS OF KETONE BODIES IN URINE OF DIABETES
Acetonuria = 248.9186
DNA helix = 523.47
Acetonuria = excessive amounts of ketone bodies
a2 + b2 = c2
a2 (Two DNA base) + b2 (Acetonuria) = c2
a2 (523.47) + b2 (248.9186)
a2 (274020.8409) + b2 (61960.46942596) = c2
a2 + b2 = 335981.31032596 = c2
a2 + b2 = 335981.31032596 / 579.63 = 579.64
a2 + b2 = 579.64 – 102.0886 (Acetoacetic acid) = 477.5514
a2 + b2 = 477.5514 – 59.5 (Acetone) = 418.0514
a2 + b2 = 418.0514 – 88.75 (β-Hydroxybutyric acid) = 329.3014
a2 + b2 = 329.3014 / 17.25 (-OH) = 19.08 - 0.58
a2 + b2 = 18.5 = H2O of urine with excessive amounts of ketone bodies
a2 + b2 = 579.64 – 56.17 (3H2O + H = 56.75) = 523.47
a2 + b2 = 523.47 = A-T=C-G = DNA base
ENERGY IN ACT BY C1
SYNTHESIS OF DISEASE
TO BE EXCESSIVE AMOUNTS OF KETONE BODIES IN URINE OF DIABETES
Acetonuria = 248.9186
DNA helix = 523.47
Acetonuria = excessive amounts of ketone bodies
a2 + b2 = c2
a2 (Two DNA base) + b2 (Acetonuria) = c2
a2 (523.47) + b2 (248.9186)
a2 (274020.8409) + b2 (61960.46942596) = c2
a2 + b2 = 335981.31032596 = c2
Light speed meter seconds = 300000000 / 335981.31032596 (m2) = 892.90
= 892.90 / 24 h = 37.20
= 37.20 / 60 men = 0.62
= 0.62 * 12.9032 sec = 8
= 4 to 8 = pH of urine
= 1.2 to 3.00 pH (by E = m2c)
= 3.00 pH of gastric juice
= pH + pOH = 14 / 12.477 pOH = 1.180
= 1.532 pH + 12.477 pOH = 14.00
= pH + pOH = 14.00,
= pOH = E = m2c,
SYNTHESIS OF DISEASE (E = m2c)
DNA base + Acetonuria = (m2)
And (m2) = 335981.31032596
For example
= 335981.31032596 (m2) / 44.254 (CO2 = 44) = 7592.111
= 7592.0173 / 30.5 C(H2O) carbohydrate = 248.9186
= 248.9186 = ketone bodies of Acetonuria
While here C(H2O) = carbohydrate as energy
So outer heat or cold is very important of body to change bio functions of inner, for example you eat m2 and for diagnose as outer c1 is very important to complete E or energy in body, supposed you eat only m2 and do not take c1 from outer side, then your diagnostic system would be damage,
SYNTHESIS OF DISEASES
Formula of medicines
DNA base + Acetonuria = excessive amounts of ketone bodies in Type I diabetes,