Sikander Aqeel

ENERGY LAW OF SIKANDER AQEEL

Apr 14th 2017, 11:20 am
Posted by aqeelsika
478 Views

ENERGY LAW IS EQUAL TO E = m2c  

 

ACETONURIA

SYNTHESIS OF DISEASE  

TO BE EXCESSIVE AMOUNTS OF KETONE BODIES IN URINE OF DIABETES

Acetonuria! Excessive amounts of ketone bodies in the urine as in diabetes mellitus or starvation  

 

WITHOUT DRUG TREATMENT       

1 = Acetoacetic acid = C4H6O3 = 102.0886 g/mol 

2 = Acetone = C3H6O = 58.08 g/mol 

3 = β-Hydroxybutyric acid = C4H7O2 = 88.75 

      Total ketone bodies = 248.9186

 

1 = Acetonuria = 248.9186  

2 = DNA helix = 523.47 = (A-T=C-G)  

 

ANSWER OF DISORDER 

Healthy disorders  

 

A = Acetonuria = 248.9186 direct value      

B = DNA helix = 523.47 = (A-T=C-G) direct value

 

ANSWER OF DISORDER 

Too Sick disorders 

FORMULA TO FIND OUT MEDICINE OF DISEASES

============================================================================ 

 

ACETONURIA

SYNTHESIS OF DISEASE  

TO BE EXCESSIVE AMOUNTS OF KETONE BODIES IN URINE OF DIABETES

       Acetonuria = 248.9186    

       DNA helix = 523.47

       Acetonuria = excessive amounts of ketone bodies    

 

        a2 + b2 = c2  

        a2 (Two DNA base)   + b2 (Acetonuria) = c2  

        a2 (523.47)         + b2 (248.9186)   

 

        a2 (274020.8409)    + b2 (61960.46942596) = c2 

 

     a2 + b2 = 335981.31032596 = c2 

     a2 + b2 = 335981.31032596 / 579.63 = 579.64

 

     a2 + b2 = 579.64 – 102.0886 (Acetoacetic acid) = 477.5514

     a2 + b2 = 477.5514 – 59.5 (Acetone) = 418.0514

     a2 + b2 = 418.0514 – 88.75 (β-Hydroxybutyric acid) = 329.3014

     a2 + b2 = 329.3014 / 17.25 (-OH) = 19.08 - 0.58 

     a2 + b2 = 18.5 = H2O of urine with excessive amounts of ketone bodies 

 

     a2 + b2 = 579.64 – 56.17 (3H2O + H = 56.75) = 523.47

     a2 + b2 = 523.47 = A-T=C-G = DNA base  

 

 

 

ENERGY IN ACT BY C1 

SYNTHESIS OF DISEASE  

TO BE EXCESSIVE AMOUNTS OF KETONE BODIES IN URINE OF DIABETES

       Acetonuria = 248.9186    

       DNA helix = 523.47

       Acetonuria = excessive amounts of ketone bodies    

 

        a2 + b2 = c2  

        a2 (Two DNA base)   + b2 (Acetonuria) = c2  

        a2 (523.47)         + b2 (248.9186)   

 

        a2 (274020.8409)    + b2 (61960.46942596) = c2 

 

     a2 + b2 = 335981.31032596 = c2 

 

Light speed meter seconds = 300000000 / 335981.31032596 (m2) = 892.90

                          = 892.90 / 24 h = 37.20

                          = 37.20 / 60 men = 0.62

                          = 0.62 * 12.9032 sec = 8

 

                          = 4 to 8 = pH of urine  

 

                          = 1.2 to 3.00 pH (by E = m2c)

                          = 3.00 pH of gastric juice

                          = pH + pOH = 14 / 12.477 pOH = 1.180

                          = 1.532 pH + 12.477 pOH = 14.00 

                          = pH + pOH = 14.00, 

                          = pOH = E = m2c,   

 

SYNTHESIS OF DISEASE (E = m2c)  

DNA base + Acetonuria = (m2) 

And (m2) = 335981.31032596

 

For example 

  = 335981.31032596 (m2) / 44.254 (CO2 = 44) = 7592.111

  = 7592.0173 / 30.5 C(H2O) carbohydrate = 248.9186

  = 248.9186 = ketone bodies of Acetonuria 

 

While here C(H2O) = carbohydrate as energy      

 

So outer heat or cold is very important of body to change bio functions of inner, for example you eat m2 and for diagnose as outer c1 is very important to complete E or energy in body, supposed you eat only m2 and do not take c1 from outer side, then your diagnostic system would be damage, 

 

SYNTHESIS OF DISEASES 

Formula of medicines 

DNA base + Acetonuria = excessive amounts of ketone bodies in Type I diabetes,  

 

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