Sikander Aqeel

ATMOSPHERE OF BERYLLIUM ON EARTH

Apr 15th 2017, 11:43 am
Posted by aqeelsika
516 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Beryllium Carbide 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

 

        a2 (25)          + b2 (16) = c2

 

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

 

Beryllium energy atmosphere = 30% * H0.55 of fusion = 16.5 hour 

 

                       Because 

                       Hour = 16.5 / 2 proton of He = 8.25-Oxygen  

                            = 8.25 – 4 proton of Be = 4.25-Beryllium 

 

Oxygen = 8 proton  

Beryllium = 4 proton 

 

  Beryllium = 8.25 * 4.25 = 35.0625

            = 35.0625 - 5.0625% (H4 = 5) = 30

            = 30

 

Chemical = 30 - 12 (C) A binary atmosphere of earth = 18 

         = 18 = Be2 = Beryllium 

 

 

Chemical formula from 16.5 hours = Be2C  

                                  = Be2C, beryllium Carbide 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 277.777% (H2O)15 = 277.5) = 30

                          = 30 = Be2C = E = m2c,       

 

 

Bookmark & Share:

Please Like Us
Please Like Us