Sikander Aqeel

ATMOSPHERE OF BERYLLIUM ON EARTH

Apr 17th 2017, 11:26 am
Posted by aqeelsika
487 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Beryllium Nitride 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

 

        a2 (25)          + b2 (16) = c2

 

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

 

Beryllium energy atmosphere = 55% * H0.55 of fusion = 30.25 hour 

 

                       Because 

                       Hour = 30.25 / 6 proton of C = 5.04-Boron  

                            = 5.04 – 4 proton of Be = 1.04-Hydrogen 

 

Boron = 5 proton  

Hydrogen = 1.25 proton 

 

  Beryllium = 5.04 * 1.04 = 5.2416

            = 5.2416 + 49.7584% (NH2 + NH2 + NH2 = 49.5) = 55

            = 55

 

Chemical = 55 - 28 (N2) A amine ion atmosphere of earth = 27 

         = 27 = Be3 = Beryllium 

 

 

Chemical formula from 30.25 hours = Be3N2  

                                  = Be3N2, Beryllium Nitride 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 151.51% (NH2)9 + H3 = 152.25) = 55

                          = 55 = Be3N2 = E = m2c,       

 

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