ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron Arsenide 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 86% * H0.54 of fusion = 46.44 hour 

                       Because 

                       Hour = 46.44 / 6 proton of C = 7.74-Oxygen  

                            = 7.74 – 5 proton of B = 2.74-Hydrogen 

Oxygen = 8 proton  

Two Hydrogen = 2.5 proton 

      Boron = 7.74 * 2.74 = 21.2076

            = 21.2076 + 64.7924% (2O2 + 0.79 = 64.79) = 86

            = 86

Chemical = 86 - 75 (As) A Positive element atmosphere of earth = 11 

         = 11 = B = Boron 

Chemical formula from 46.44 hours = BAs  

                                  = BAs, Boron Arsenide 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 39.71% (H2O)2 + H2 = 39.5) = 86

                          = 86 = BAs = E = m2c,