ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron (III) arsenate 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 150% * H0.54 of fusion = 81 hour 

                       Because 

                       Hour = 81 / 6 proton of C = 13.5-Silicone  

                            = 13.5 – 5 proton of B = 8.5-Fluorine 

Silicone = 14 proton  

Fluorine = 9 proton 

      Boron = 13.5 * 8.5 = 114.75

            = 114.75 + 35.25% (H2O2 + 0.75 = 35.25) = 150

            = 150

Chemical = 150 - 75 (As) A salt and ester atmosphere of earth = 75 

         = 75 – 64 (O4) = 11 

         = 11 = B = Boron 

Chemical formula from 81 hours = BAsO4  

                               = BAsO4, Boron (III) arsenate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 22.76% (H2O + H3 = 22.25) = 150

                          = 150 = BAsO4 = E = m2c,