ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron tribromide 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 251% * H0.54 of fusion = 135.54 hour 

                       Because 

                       Hour = 135.54 / 6 proton of C = 22.59-Vanadium  

                            = 22.59 – 5 proton of B = 17.59-Argon 

Vanadium = 23 proton  

Argon = 18 proton 

      Boron = 22.59 * 17.59 = 397.3581

            = 397.3581 + 146.3581% (H2O)7 + O = 145.5) = 251

            = 251

Chemical = 251 - 240 (Br3) A sea water atmosphere of earth = 11 

         = 11 = B = Boron 

Chemical formula from 81 hours = BBr3  

                               = BBr3, Boron Tribromide 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 13.60% (CH = 13.25) = 251.125

                          = 251 = BBr3 = E = m2c,