ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron Tri-chloride 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 116% * H0.54 of fusion = 62.64 hour 

                       Because 

                       Hour = 62.64 / 6 proton of C = 10.44-Sodium  

                            = 10.44 – 5 proton of B = 5.44-Carbon 

Sodium = 11 proton  

Carbon = 6 proton 

      Boron = 10.44 * 5.44 = 56.7936

            = 56.7936 + 59.2064% (H2O)3 + H3 = 59.25) = 116

            = 116

Chemical = 116 - 105 (Cl3) A chlorine atmosphere of earth = 11 

         = 11 = B = Boron 

Chemical formula from 62.64 hours = BCl3  

                                  = BCl3, Boron Tri-chloride 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 29.44% (2CH2 + H2 = 29) = 116

                          = 116 = BCl3 = E = m2c,