ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron Iodide 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 392% * H0.54 of fusion = 725.92 hour 

                       Because 

                       Hour = 725.92 / 33 proton of As = 21.99-Titanium  

                            = 21.99 – 5 proton of B = 16.99-Chlorine 

Titanium = 22 proton   

Chlorine = 17 proton 

      Boron = 21.99 * 16.99 = 373.6101

            = 373.6101 + 18.3899% (H2O = 18.5) = 392 

            = 392

Chemical = 392 - 381 (I3) A sea salt type atmosphere of earth = 11 

         = 11 = B = Boron 

Chemical formula from 725.92 hours = BI3  

                                   = BI3, Boron Iodide 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 8.7125% (H7 = 8.75) = 392

                          = 392 = BI3 = E = m2c,