Sikander Aqeel

GENETIC DISORDERS LAW OF SIKANDER AQEEL

Apr 26th 2017, 11:37 am
Posted by aqeelsika
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SECOND BASE OF RNA FOR GENETIC DISORDERS

ACHONDROPLASIA 

SYNTHESIS OF DISEASE  

WITHOUT DRUGS GENETIC TREATMENT 

Achondroplasia! An inherited skeletal disorder beginning before birth' cartilage is converted to bone resulting in dwarfism, 

 

The Skeleton disorder belongs with sick spinal cord by birth, which do not complete a circle of 20 year growth with 70 inch height, that the sick spinal cord complete own circle in 4, 5, or 6 year with 40 in height, 

 

The spinal nerves have 31 joints attached with body arms legs through the pipe line of meat, if this 31 joint of spinal nerve complete own 20 year growth processer then height would be 70 inch of body, and if this 31 joint of spinal nerve complete own circle in 4 year growth processer then height would be 40 inch of body, or in easy words the Somatic nervous system act only 4 year for dwarfism body, while for normal body height Somatic nervous system takes 20 year to complete growth of 70 inch height,    

 

THE SOMATIC NERVOUS SYSTEM 

Somatic nervous system = care of Skeleton, joints, tissues, and skin, 

Complete skeleton = Vitamin-D 

Parathyroid hormone (PTH) = Kidney, Bone cells     

 

A = Vitamin-D + (PTH) = 11745.64 direct value      

B = Two DNA helix = 1046.94 = (A-T=C-G)2 direct value

 

ACHONDROPLASIA 

SYNTHESIS OF DISEASE  

WITHOUT DRUGS GENETIC TREATMENT 

       Vitamin-D + (PTH) = 11745.64   

       Two DNA helix = 1046.94

       Achondroplasia = short period of growth,   

 

 

Vitamin-D + (PTH) = 11745.64 + 1046.94 DNA base = 12792.58

                  = 12792.58

 

           = 12792.58 – 134.25-Leucine = 12658.33

           = 12658.33 / 112.50 = 112.51

           = 112.51 + 14.49 (N) = 127

           = 127 = I = Iodine  

 

 

Leucine-134.25! Helps with bone healing,   

 

Iodine-127! Very important for thyroid gland                  

 

Leucine-134.25 m/g mRNA CODE    

Leucine-134.25 + 127 I = 261.25 mole / 127 I = 2.05 times compound of Iodine 

 

2.05 * 127 I = 260.35

2.05 times compound of Iodine = 260.35

 

TO START GENETIC SYSTEM 

Leucine-134.25 

Iodine-127 

2.05 times compound of Iodine = 260.35

Uracil = C4H4N2O2 = 112.0868 g/mol = (U) 

 

        a2 + b2 [3Th part] = c2  

        a2 + b2 (amino acid) = c2  

 

        a2 (Uracil)           + b2 (60 minute) [amino acid] = c2  

        a2 (112.0868)         + b2 (60 minute) [amino acid] = c2   

        a2 (12563.45073424)   + b2 (3600) [amino acid] = c2 

 

        a2 + b2 = 16163.45 [amino acid] = c2 

        a2 + b2 = 16163.45 / 127.13 = 127.14 

 

        a2 + b2 = 127.14 * 260.35 (2.05 times Iodine) = 33100.899

        a2 + b2 = 33100.899 / 3 triple RNA = 11033.633

        a2 + b2 = 11033.633 - 9631.439% (Leucine-134.25) = 1402.194

        a2 + b2 = 1402.194 = CUU CUC CUA CUG = Leu from Iodine, 

 

Leucine = 9631.439% / 134.25 Leu = 71.74 sets in mRNA   

Leucine = CUU CUC CUA CUG

 

        JOINING OF ADENINE WITH THYMINE 

        JOINING OF GUANINE WITH CYTOSINE

 

WHAT IS PRESENCE OF METAL IN CELL FLUID?  

Leucine = CUU CUC CUA CUG = 1402.194 Leu + 127 I = 1529.194

 

      Start 

      a2 + b2 = 16163.45 / 1529.194 Leu + I = 10.56 or 11 amino acids to take start from AUA-Isoleucine

 

      End 

      a2 + b2 = 1402.194 Leu = 6 = CUC-Leucine end 

 

        JOINING OF ADENINE GUANINE = PURINE 

        JOINING OF URACIL CYTOSINE = PYRIMIDINE 

 

 

        FOR STOP TO RNA 

        If started from left side to codon chart 

        Then Start = AUA-Isoleucine mRNA = 11 amino acid, 

        Then End = CUC-Leucine = 6 amino acids,  

 

 

Or to make protein under the Leucine + Isoleucine use only 5-CUU-Leucine codes of RNA, 

Start = 11 – 6 end = 5-CUU-Leucine codon RNA 

 

SOLUTION OF DISEASE

Start AUA-Isoleucine = A = Second base 

End CUC-Leucine = C = Second base 

Center CUU-Leucine = C = Second base 

 

READING LAW OF CODON 

Up to down = ACC -------rain fall from sky like up to down 

Down to up = CCA -------rain water again go up through the roots of plant 

Center = CAC CCA -------rate of creatures or beginning or life  

 

TOTAL SECOND BASE WITH GOOD NEWS    

GENETIC MUTATION

mRNA ACC 2th Threonine = Threonine 2th DNA base TGG = ?-T=?-G = Lost AC   

mRNA CCA 3th Proline = Proline 3th DNA base GGT = ?-T=?-G = Lost AC

 

mRNA CAC 2th Histidine = Histidine 2th DNA base GTG = ?-T=?-G = Lost AC

mRNA CCA 3th Proline = Proline 3th DNA base GGT = ?-T=?-G = Lost AC

 

REPLICATION OF DNA

First helix = ATTGCAT  

Second helix = TAACGTA  

 

First helix = ?TTG?AT

Second helix = TA??GTA

 

First lost? = AC

Second lost? = AC 

 

Total profit = ACA-C in base

Total profit = ACA-C in Cysteine amino acid

 

Two DNA base + Vitamin-D + (PTH) = ACA-C

Two DNA base + Vitamin-D + (PTH) ACA-C = UGU, UGC, mRNA Cysteine, 

Two DNA base + Vitamin-D + (PTH) ACA-C - ACA, ACG, tRNA Cysteine, 

Two DNA base + Vitamin-D + (PTH) ACA-C = ACA, ACG, DNA Cysteine, 

 

The mRNA getting right information with tRNA and DNA about Cysteine, 

Because Cysteine Precursor to Chondroitin Sulfate, the main component of cartilage, and cartilage tough elastic tissue; mostly convert to bone in **, in normal body growth, and his opposite is a dwarfism,   

 

GENETIC DISORDERS 

Two DNA base + Vitamin-D + (PTH)= ACA-C

 

Chemical value of triple one (111) 

Chemical value of Adenine (135.13) m/g 

 

--------135.13 / 2-C = 67.56 = 3H2O + C = normal height     

--------135.13 / 3-C = 45.04 = COOH 

--------135.13 / 4-C = 33.78 = OHO   

--------135.13 / 5-C = 27.02 = CH + N 

--------135.13 / 6-C = 22.52 = H2O + H3 

--------135.13 / 7-C = 19.30 = H2O 

--------135.13 / 8-C = 16.89 = O 

--------135.13 / 9-C = 15.01 = NH---------- dwarfism, 

 

Diseases solution is 9 Cytosine, because Cytosine = 9 * 135.13 = 1216.17 

                                                  = 1216.17 / 18-C / 67.56

                                                  = 67.56 = 3H2O + C healthy stomach with carbon chain,

 

Sick cells = 9 percent less A-T=C-G bases in two helix = C dry carbon 

Healthy cells = 2 percent A-T=C-G bases in two helix = 3H2O oily and acidic

 

Or in more easy words 

 

Oldness = 9 percent less A-T=C-G bases in two helix = C dry carbon 

Newborn = 2 percent A-T=C-G bases in two helix = 3H2O oily and acidic  

 

 

 

 

 

 

 

 

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