ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron Nitride 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 25% * H0.54 of fusion = 13.5 hour 

                       Because 

                       Hour = 13.5 / 2 proton of He = 6.75-Nitrogen  

                            = 6.75 – 5 proton of B = 1.75-Hydrogen 

Nitrogen = 7 proton   

Hydrogen = 1.25 proton 

      Boron = 6.75 * 1.75 = 11.8125

            = 11.8125 + 13.1875% (CH = 13.25) = 25 

            = 25

Chemical = 25 - 14 (N) A Electropositive atmosphere of earth = 11 

         = 11 = B = Boron 

Chemical formula from 13.5 hours = BN  

                                 = BN, Boron Nitride 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 136.612% (7H2O + H6 = 137) = 25

                          = 25 = BN = E = m2c,