ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boric Acid 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 45.5% * H0.54 of fusion = 24.57 hour 

                       Because 

                       Hour = 24.57 / 2 proton of He = 12.285-Magnesium  

                            = 12.285 – 5 proton of B = 7.285-Nitrogen 

Magnesium = 12 proton   

Nitrogen = 7 proton 

      Boron = 12.285 * 7.285 = 89.496225

            = 89.496225 = 43.996225% (CO2 = 44) = 45.5  

            = 45.5

Chemical = 45.5 - 34.5 (OH)2 A food preservation atmosphere of earth = 11 

         = 11 = B = Boron 

Chemical formula from 24.57 hours = B(OH)2  

                                 = B(OH)2, Boric Acid 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 75.061% (CO2 + CH2OH = 75.75) = 45.5

                          = 45.5 = B(OH)2 = E = m2c,