ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron chloride 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 162% * H0.54 of fusion = 87.48 hour 

                       Because 

                       Hour = 87.48 / 6 proton of C = 14.58-Phosphrus  

                            = 14.58 – 5 proton of B = 9.58-Neon 

Phosphorus = 15 proton   

Neon = 10 proton 

      Boron = 14.58 * 9.58 = 139.6764

            = 139.6764 + 22.3236 (H2O + H3 = 22.25) = 162

            = 162

Chemical = 162 - 140 (Cl4) A Ion atmosphere of earth = 22 

         = 22 = B2 = Boron  

Chemical formula from 87.48 hours = B2Cl4

                                  = B2Cl4, Boron chloride 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 21.082 (H2O + H2 = 21) = 162

                          = 162 = B2Cl4 = E = m2c,