ATMOSPHERE OF BORON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Boron Hydride 

        Boron = 11-B  

        Boron = 11 

        Boron = 5 proton 

        Boron = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (5)   

        a2 (36)          + b2 (25) = c2

        a2 + b2 = 61 = c2 

        a2 + b2 = 61 / 11-B = 5.54

        a2 + b2 = 5.54 = 5 proton + H0.54

Boron energy atmosphere = 29.5% * H0.54 of fusion = 15.93 hour 

                       Because 

                       Hour = 15.93 / 2 proton of He = 7.965-Oxygen  

                            = 7.965 – 5 proton of B = 2.965-Lithium 

Oxygen = 8 proton   

Lithium = 3 proton 

      Boron = 7.965 * 2.965 = 23.616225

            = 23.616225 + 5.883775 (H5 = 6.25) = 29.5

            = 29.5

Chemical = 29.5 – 7.5 (H6) A union of hydrogen atmosphere of earth = 22 

         = 22 = B2 = Boron  

Chemical formula from 15.93 hours = B2H6

                                  = B2H6, Boron Hydride 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 61 (m2) = 4918032.78

                          = 4918032.78 / 24 hour = 204918.0325

                          = 204918.0325 / 60 minute = 3415.30

                          = 3415.30 / 115.77 (B2H6)4 = 118) = 29.5

                          = 29.5 = B2H6 = E = m2c,