ACID-FAST
SYNTHESIS OF DISEASE
WITHOUT DRUGS GENETIC TREATMENT
Acid-fast! Histology not easily decolorized by acid solutions' pertains to micro-organisms (especially the tubercle bacillus that causes tuberculosis)
Tuberculosis! Infection transmitted by inhalation or ingestion of tubercle bacilli and manifested in fever and small lesions (usually in the lungs, but in various other part of the body in acute stage)
Mycobacterium! Rod shaped bacteria some saprophytic or causing diseases of tuberculosis,
WITHOUT DRUG TREATMENT
1 = Sputum of lung = 95% water
1 = Mycobacterium = 58% body
1 = Silicon = 28 mass as in clay
1 = nitrogen = 14 mass as in clay
1 = total = 195 Tuberculosis
1 = Tuberculosis = 195
2 = One DNA helix = 523.47 = (A-T=C-G)
ANSWER OF DISORDER
Healthy disorders
A = Tuberculosis = 195 = direct value
B = DNA helix = 523.47 = (A-T=C-G) = direct value
ACID-FAST
SYNTHESIS OF DISEASE
WITHOUT DRUGS GENETIC TREATMENT
Tuberculosis = 195
DNA helix = 523.47
Tuberculosis = Mycobacterium,
Tuberculosis = 195 + 523.47 DNA base = 718.47
= 718.47
= 718.47 – 117.25-Proline = 601.22
= 601.22 / 24.51 = 24.52
= 24.52 - 1.52 H = 23
= 23 = Na = Sodium,
Proline + Sodium = Saliva
Proline-117.25! Involved in keeping heart and lungs muscle strong,
Sodium-23! Deposit in food duct or in esophagus, if sodium would be less in esophagus then bacteria involve in lungs,
Proline-117.25 m/g mRNA CODE
Proline-117.25 + 23 Na = 140.25 mole / 23 Na = 6.09 times compound of Na
6.09 * 23 Na = 140.07
6.09 times compound of Na = 140.07
TO START GENETIC SYSTEM
Proline-117.25
Sodium-23
6.09 times compound of Na = 140.07
Uracil = C4H4N2O2 = 112.0868 g/mol = (U)
a2 + b2 [3Th part] = c2
a2 + b2 (amino acid) = c2
a2 (Uracil) + b2 (60 minute) [amino acid] = c2
a2 (112.0868) + b2 (60 minute) [amino acid] = c2
a2 (12563.45073424) + b2 (3600) [amino acid] = c2
a2 + b2 = 16163.45 [amino acid] = c2
a2 + b2 = 16163.45 / 127.13 = 127.14
a2 + b2 = 127.14 * 140.07 (6.09 times Sodium) = 17808.4998
a2 + b2 = 17808.4998 / 3 triple RNA = 5936.1666
a2 + b2 = 5936.1666 - 4537.9198% (Proline-117.25) = 1398.2468
a2 + b2 = 1398.2468 = CCU CCC CCA CCG = pro from Sodium,
Proline = 4537.9198% / 117.25 Pro = 38.70 sets in mRNA
Proline = CCU CCC CCA CCG
JOINING OF ADENINE WITH THYMINE
JOINING OF GUANINE WITH CYTOSINE
WHAT IS PRESENCE OF METAL IN CELL FLUID?
Proline = CCU CCC CCA CCG = 1398.2468 Pro + 23 Na = 1421.2468
Start
a2 + b2 = 16163.45 / 1421.2468 (Pro + Na) = 11.37 or 11 amino acids to take start from AUA-Isoleucine
End
a2 + b2 = 1398.2468 Pro = 21 = CCU-Proline end
JOINING OF ADENINE GUANINE = PURINE
JOINING OF URACIL CYTOSINE = PYRIMIDINE
FOR STOP TO RNA
If started from left side to codon chart
Then Start = AUA-Isoleucine mRNA = 11 amino acid,
Then End = CCU-Proline = 21 amino acids,
Or to make protein under the Proline + Isoleucine use only 10-AUC-Isoleucine codes of RNA,
End = 21 – 11 start = 10-AUC-Isoleucine codon RNA
SOLUTION OF DISEASE
Start AUA-Isoleucine = A = third base
End CCU-Proline = U = third base
Center AUC-Isoleucine = C = third base
READING LAW OF CODON
Up to down = AUC -------rain fall from sky like up to down
Down to up = CUA -------rain water again go up through the roots of plant
Center = UAC UCA -------rate of creatures or beginning or life
TOTAL THIRD BASE WITH GOOD NEWS
GENETIC MUTATION
mRNA AUC 2th Isoleucine = Arginine 2th DNA base TAG = A-T=?-G = Lost C
mRNA CUA 5th Leucine = Leucine 5th DNA base GAT = A-T=?-G = Lost C
mRNA UAC 2th Tyrosine = Tyrosine 2th DNA base ATG = A-T=?-G = Lost C
mRNA UCA 3th Serine = Serine 3th DNA base AGT = A-T=?-G = Lost C
REPLICATION OF DNA
First helix = ATTGCAT
Second helix = TAACGTA
First lost? = C + C
Second lost? = C + C
For aliment C2 + C2 = CCC-C
Total profit = CCC-C in base
Total profit = CCC-C in Glycine amino acid
DNA base + Tuberculosis = CCC-C = Glycine
DNA base + Tuberculosis = CCC-C = Glycine
The mRNA getting right information with tRNA and DNA about Glycine,
Because CCC-Glycine Deficiency rise up Chronic Fatigue Syndrome type Tuberculosis,
GENETIC MUTATION WITH LAST DNA BASE
mRNA AUC 2th Isoleucine = Last DNA base TAT = A-T=?-? = Lost CG
mRNA CUA 5th Leucine = Last DNA base GAC = A-?=C-G = Lost T
mRNA UAC 2th Tyrosine = Last DNA base ATG = A-T=?-G = Lost C
mRNA UCA 3th Serine = Last DNA base TCG = ?-T=C-G = Lost A
REPLICATION OF DNA
First lost? = CG + T
Second lost? = C + A
For aliment CGTCA = CGT-CA
Total profit = CGT-CA in base
Total profit = CGT-CA in Alanine amino acid
DNA base + Tuberculosis = CGT = Alanine
DNA base + Tuberculosis = CGT = Alanine
The mRNA getting right information with tRNA and DNA about Alanine,
Because CGT-Alanine! Important source of energy for muscle of lungs and other all body, Boosts immune system by producing antibodies, Alanine deficiency seen Tuberculosis type fatigue,
GENETIC TREATMENT AND MEDICINE FORMULA
SYNTHESIS OF DISEASES
6.09 times Sodium + 38.70 sets Proline + Isoleucine = CCC + CGT
Sodium = 6.09 m/g
Proline = 38.70 m/g
Isoleucine = 55.21 m/g
Total = 100 m/g = CCC + CGT,