Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

May 22nd 2017, 11:59 am
Posted by aqeelsika
560 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Chloroacetic acid 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 94.75% * H0.01 of fusion = 0.9475 hour 

 

                       Because 

                       Hour = 0.9475 * 13 proton of Al = 12.3175-Magnesium   

                            = 12.3175 – 6 proton of C = 6.3175-Carbon 

 

Magnesium = 12 proton   

Carbon = 6 proton 

 

Carbon = 12.3175 * 6.3175 = 77.81580625

       = 77.81580625 + 16.93419375 (O + 0.93419375 = 16.93419375) = 94.75

       = 94.75

 

Chemical = 94.75 – 35 (Cl) A chlorine atmosphere of earth = 59.75

         = 59.75 – 32 (O2) = 27.75 

         = 27.75 – 3.75 (H3) = 24   

         = 24 = C2 = Carbon   

 

 

Chemical formula from 0.9475 hours = CH2ClCOOH

                                   = CH2ClCOOH, Chloroacetic acid 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 30.538 (NO = 30) = 94.75

                          = 94.75 = CH2ClCOOH = E = m2c,         

 

 

Bookmark & Share:

Please Like Us
Please Like Us