Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

May 25th 2017, 11:12 am
Posted by aqeelsika
434 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Ethylene glycol 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 64.75% * H0.01 of fusion = 0.6475 hour 

 

                       Because 

                       Hour = 0.6475 * 15 proton of P = 9.7125-Neon   

                            = 9.7125 – 6 proton of C = 3.7125-Beryllium 

 

Neon = 10 proton   

Beryllium = 4 proton 

 

Carbon = 9.7125 * 3.7125 = 36.05765625

       = 36.05765625 + 28.69234375 (CH2 + CH2 = 29) = 64.75

       = 64.75

 

Chemical = 64.75 – 32 (O2) Antifreeze type atmosphere of earth = 32.75

         = 32.75 – 8.75 (H7) = 24   

         = 24 = C2 = Carbon   

 

 

Chemical formula from 0.6475 hours = CH2OHCH2OH

                                   = CH2OHCH2OH, Ethylene glycol 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 44.687 (CO2 + 0.687 = 44.687) = 64.75

                          = 64.75 = CH2OHCH2OH = E = m2c,          

 

Bookmark & Share:

Please Like Us
Please Like Us