Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

May 30th 2017, 11:40 am
Posted by aqeelsika
457 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

2-Butene 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 58% * H0.01 of fusion = 0.58 hour 

 

                       Because 

                       Hour = 0.58 * 19 proton of K = 11.02-Sodium   

                            = 11.02 – 6 proton of C = 5.02-Boron 

 

Sodium = 11 proton   

Boron = 5 proton 

 

Carbon = 11.02 * 5.02 = 75.2724

       = 55.3204 + 2.6796 (H2 = 2.5) = 58

       = 58

 

Chemical = 58 – 10 (H8) Synthetic rubbers type atmosphere of earth = 48

         = 48 = C4 = Carbon 

 

Synthetic rubbers type such as branches of tree, or such as each person has bound with home rubber, therefore they come back home through this synthetic rubbers, and sometimes this rubber becomes loss, and then they person come late in home everyday, it was Synthetic rubbers type atmosphere of earth,           

 

Chemical formula from 0.58 hours = CH3CHCHCH3

                                 = CH3CHCHCH3, 2-Butene 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 49.88 (CO2 + H4 = 49) = 58

                          = 58 = CH3CHCHCH3 = E = m2c,          

 

 

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