ACTINOMYCOSIS
SYNTHESIS OF DISEASE
WITHOUT DRUGS GENETIC TREATMENT
(Auto DNA Engineering)
Actinomycosis! Disease of cattle that can be transmitted to humans; results from infection with actinomycetes; characyerized by hard swellings that exude pus through lon sinuses,
Actinomycosis is primarily caused by any of several members of the bacterial genus Actinomyces. These bacteria are generally anaerobes, In animals, they normally live in the small spaces between the teeth and gums, causing infection only when they can multiply freely in anoxic environments. An affected human often has recently had dental work, poor oral hygiene, periodontal disease, radiation therapy, or trauma (broken jaw) causing local tissue damage to the oral mucosa, all of which predispose the person to developing actinomycosis.
SILENT RESEARCH
Basically bacteria increses heat and then gums swellings,
Inner interference =
Outer interference = outer
WITHOUT DRUG TREATMENT
1 = Actinomycosis act = deficiency of Proline + Lysine
1 = Lysine = TTT, TTC (DNA base)
1 = Lysine = A0 + T5 + C1 + G0
1 = Lysine = A-0 + T-630.55 + C-111.1 + G-0
1 = Lysine DNA base = 741.65
2 = Proline = C5H9NO2 = 117.25 m/g
1 = Proline = 117.25
2 = Lysine DNA base = 741.65 = (0-T=C-0)
ANSWER OF DISORDER
Too Sick disorders
FORMULA TO FIND OUT MEDICINE OF DISEASES
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ACTINOMYCOSIS
SYNTHESIS OF DISEASE
WITHOUT DRUGS GENETIC TREATMENT
Proline = 117.25
Lysine DNA base = 741.65
Actinomycosis = deficiency of Proline + Lysine,
Proline = 117.25 + 741.65 Lysine DNA base = 858.9
= 858.9
Lysine deficiency causes of infectiona and bacteria,
Proline use as to do less deficiency of lysine
= 858.9 – 149.5-Lysine = 709.4
= 709.4 / 26.63 = 26.63
= 26.63 - 2.63 (H2) = 24
= 24 = Magnesium-24,
= 26.63 = Mg+H2 = 26.5
Lysine-149.5! Deficiency rise up virus and infections,
Mg+H2-26.5! Deficiency rise up Actinomycosis diseases of lungs and the intestines,
Lysine-149.5 m/g mRNA CODE
Lysine-149.5 + 26.5 Mg+H2 = 176 mole / 26.5 Mg+H2 = 6.64 times compound of Mg+H2,
6.64 * 26.5 Mg+H2 = 175.96
6.64 times compound of Mg+H2 = 175.96
TO START GENETIC SYSTEM
Lysine-149.5
Mg+H2-26.5
6.64 times compound of Mg+H2 = 175.96
Uracil = C4H4N2O2 = 112.0868 g/mol = (U)
a2 + b2 [3Th part] = c2
a2 + b2 (amino acid) = c2
a2 (Uracil) + b2 (60 minute) [amino acid] = c2
a2 (112.0868) + b2 (60 minute) [amino acid] = c2
a2 (12563.45073424) + b2 (3600) [amino acid] = c2
a2 + b2 = 16163.45 [amino acid] = c2
a2 + b2 = 16163.45 / 127.13 = 127.14
a2 + b2 = 127.14 * 175.96 (6.64 times Mg+H2) = 22371.5544
a2 + b2 = 22371.5544 / 3 triple RNA = 7457.1848
a2 + b2 = 7457.1848 - 6630.4048% (Lysine-149.5) = 826.78
a2 + b2 = 826.78 = AAA AAG = Lys from Boron nitride,
Lysine = 6630.4048% / 149.5 Lys = 44.35 sets in mRNA
Lysine = AAA AAG = 826.78
JOINING OF ADENINE WITH THYMINE
JOINING OF GUANINE WITH CYTOSINE
WHAT IS PRESENCE OF METAL IN CELL FLUID?
Lysine = AAA AAG = 826.78 Lys + 26.5 Mg+H2 = 853.28
Start
a2 + b2 = 16163.45 / 853.28 (Lys + Mg+H2) = 18.94 or 19 amino acids to take start from UCA-Serine mRNA
End
a2 + b2 = 826.78 Lys = 44 = AAG-Lysine end mRNA
JOINING OF ADENINE GUANINE = PURINE
JOINING OF URACIL CYTOSINE = PYRIMIDINE
FOR STOP TO RNA
If started from left side to codon chart
Then Start = UCA-Serine mRNA = 19 amino acid,
Then End = AAG-Lysine = 44 amino acids,
Or to make protein under the Lysine + Serine use only 25-ACU-Threonine codes of RNA,
End = 44 – 19 Start = 25-ACU-Threonine codon RNA
SICK CODON LAW OF SIKANDER AQEEL
In which first alphabet will be count two time, that faster DNA system two times add to itself, as to rise up diseases, if treatment amino acid come back again, that they will called disease,
ACTINOMYCOSIS
SOLUTION OF DISEASE
Start UCA-Serine = A = third base
End AAG-Lysine = G = third base
Center ACU-Threonine = U = third base
SICK CODON = FASTER DNA FUNCTION,
Up to down = AAG -------A counted two times from up side
Down to up = UUG ------- U counted two times from down side
Center = GGA GGU ------- G counted two times from center,
TOTAL THIRD BASE WITH GOOD NEWS
GENETIC MUTATION
mRNA AAG 2th Lysine = Lysine 2th DNA base TTC = ?-T=C-? = Lost AG
mRNA UUG 2th Leucine = Leucine 2th DNA base AAC = A-?=C-? = Lost TG
mRNA GGA 2th Glycine = Glycine 2th DNA base CCG = ?-?=C-G = Lost AT
mRNA GGU 1th Glycine = Glycine 1th DNA base CCA = A-?=C-? = Lost TG
Total DNA base = TTC AAC CCG CCA + AG TG AT TG = (4) A-T=C-G complete DNA base
REPLICATION OF DNA
First helix = ATTGCAT
Second helix = TAACGTA
First lost? = AG TG
Second lost? = AT TG
Right aliment AGT-GAT-TG
Wrong aliment AG-TGA-TTG
Total profit = AG-TGA-TTG in base
Total profit = AG-TGA-TTG in amino acid
Right DNA answer = AG-TGA-TTG = TTC AAC CCG CCA
Right amino acid Lysine = TTC DNA second base,
The mRNA getting right information with tRNA and DNA about Lysine,
PARTNERSHIP OF AMINO ACID OF DAMAGE DNA,
Because TGA - Threonine! Normal condition
Because TTG - Asparagine! Normal condition
Because TTC - Lysine! Bacterial growth as Actinomycosis
Because AAC - Leucine! Help bacterial growth as Actinomycosis
Because CCG – Glycine! Sick or weak glutathione peroxidase
Because CCA – Glycine! Sick or weak glutathione peroxidase
This theory is contain on return again own self, or diseases again return in diseases, while health does not return own self, that the healthy DNA system continuous jump to own third base,