Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jul 8th 2017, 11:19 am
Posted by aqeelsika
480 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Dimethyl sulfide 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 63.5% * H0.01 of fusion = 0.33 hour 

 

                       Because 

                       Hour = 0.635 * 20 proton of Ca = 12.7-Aluminum   

                            = 12.7 – 6 proton of C = 6.7-Nitrogen 

 

Aluminum = 13 proton    

Nitrogen = 7 proton  

 

Carbon = 12.7 * 6.7 = 85.09

       = 85.09 - 21.59 (H2O + H2.5 = 21.625) = 63.5

       = 63.5

 

Chemical = 63.5 – 32 (S) Electron-positive type atmosphere of earth = 31.5

         = 31.5 – 7.5 (H6) = 24

         = 24 = C2 = Carbon  

 

 

Electron-positive type atmosphere,     

 

Chemical formula from 0.635 hours = CH3SCH3

                                  = CH3SCH3, Dimethyl sulfide 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 45.56 (2H2O + H7 = 45.75) = 63.5

                      = 63.5 = CH3SCH3 = (E = m2c),  

 

 

Bookmark & Share:

Please Like Us
Please Like Us