Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jul 10th 2017, 11:21 am
Posted by aqeelsika
513 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Methanethiol 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 49% * H0.01 of fusion = 0.49 hour 

 

                       Because 

                       Hour = 0.49 * 22 proton of Ti = 10.78-Sodium   

                            = 10.78 – 6 proton of C = 4.78-Boron 

 

Sodium = 11 proton    

Boron = 5 proton  

 

Carbon = 10.78 * 4.78 = 51.5284

       = 51.5284 - 2.5284 (H2 = 2.5) = 49

       = 49

 

Chemical = 49 – 32 (S) Methanethiol type atmosphere of earth = 17

         = 17 – 5 (H4) = 12

         = 12 = C = Carbon  

 

 

Methanethiol type atmosphere, 

 

Chemical formula from 0.49 hours = CH3SH

                                 = CH3SH, Methanethiol 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 59.051 (3H2O + H3 = 59.25) = 49

                      = 49 = CH3SH = (E = m2c),  

 

 

 

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