Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jul 18th 2017, 11:21 am
Posted by aqeelsika
656 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Cyanide ion 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 28% * H0.01 of fusion = 0.28 hour 

 

                       Because 

                       Hour = 0.28 * 33 proton of As = 9.24-Fluorine   

                            = 9.24 – 6 proton of C = 3.24-Lithium 

 

Fluorine = 9 proton    

Lithium = 3 proton 

 

Carbon = 9.24 * 3.24 = 29.9376

       = 29.9376 - 1.9376 (H) = 28

       = 28

 

Chemical = 28 – 16 (N) Organic compounds type atmosphere of earth = 12

         = 12 = C = Carbon  

 

Organic compounds type atmosphere, such as organic compounds are filled in each creature of earth, so it will be called the Organic compounds type atmosphere of earth,      

 

Chemical formula from 0.62 hours = CN-

                                 = CN-, Cyanide ion  

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 103.339 (H2O)5 + H9 = 103.75) = 28

                      = 28 = CN- = (E = m2c),  

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